This problem involves finding the minimum number of keypresses needed to type a given string, given constraints on the mapping of characters to buttons on a keypad. The constraints are:
The optimal strategy is to assign the most frequent characters to the buttons, and then assign the next most frequent characters to the same buttons. This is a greedy approach.
Count Character Frequencies: First, count the occurrences of each character in the input string s
. We can use a hash table (or a simple array since we only have 26 lowercase letters) for efficient counting.
Sort Frequencies: Sort the character frequencies in descending order. The characters with the highest frequencies will require the fewest key presses.
Assign to Buttons: Iterate through the sorted frequencies and assign characters to buttons. Since each button can map to at most 3 characters, we'll cycle through the 9 buttons repeatedly. For example:
Calculate Total Keypresses: For each character, the number of keypresses is determined by its position within its button's assignment:
Return Total: Sum up the keypresses for all characters to get the minimum total.
Time Complexity: O(N + K log K), where N is the length of the string and K is the number of unique characters (26 in this case). The dominant factor is sorting the frequencies (O(K log K)). Counting character frequencies is O(N).
Space Complexity: O(K) to store character frequencies. Since K is a constant (26), the space complexity is considered O(1).
from collections import Counter
def minimumKeypresses(s: str) -> int:
"""
Calculates the minimum number of keypresses needed to type the string s.
"""
# Count character frequencies
freq = Counter(s)
frequencies = sorted(freq.values(), reverse=True)
total_keypresses = 0
keypad_index = 0 # Index of the current button (0-8)
press_count = 1 # Number of presses for the current character on a button
for i, count in enumerate(frequencies):
total_keypresses += count * press_count
press_count += 1
if press_count > 3:
press_count = 1 #Reset for the next button
keypad_index = (keypad_index + 1) % 9 # Cycle through buttons
return total_keypresses
The code in other languages (Java, C++, Go, TypeScript) follows a very similar structure, using appropriate data structures and syntax for each language. The core algorithmic steps remain the same.