This problem involves querying two tables, NPV
and Queries
, to find the Net Present Value (NPV) for each query in the Queries
table. The solution uses a LEFT JOIN
operation in SQL.
Understanding the Tables:
NPV
Table: Contains id
, year
, and npv
columns representing the inventory ID, year, and its NPV. The combination of id
and year
is the primary key, ensuring uniqueness.Queries
Table: Contains id
and year
columns representing the inventory ID and year for each query. Again, the combination of id
and year
forms the primary key.The Approach:
The core idea is to combine the Queries
table with the NPV
table based on matching id
and year
values. We use a LEFT JOIN
because we want to include all rows from the Queries
table, even if there's no matching entry in the NPV
table. If there's no match, the npv
value from the NPV
table will be NULL
.
SQL Solution (MySQL):
SELECT q.*, IFNULL(npv, 0) AS npv
FROM
Queries AS q
LEFT JOIN NPV AS n USING (id, year);
Code Breakdown:
SELECT q.*, IFNULL(npv, 0) AS npv
: This selects all columns (*
) from the Queries
table (aliased as q
) and a calculated column named npv
. IFNULL(npv, 0)
handles cases where the npv
from the NPV
table is NULL
. It replaces NULL
with 0, as specified in the problem description.
FROM Queries AS q LEFT JOIN NPV AS n USING (id, year)
: This specifies the join operation.
LEFT JOIN
: Ensures that all rows from the Queries
table are included in the result.NPV AS n
: Aliasing the NPV
table as n
for brevity.USING (id, year)
: This concisely specifies that the join should be performed on the id
and year
columns, which are common to both tables.Time Complexity Analysis:
The time complexity of this SQL query depends heavily on the database engine's optimization strategies and the size of the tables. In a simplified scenario, a LEFT JOIN
operation, in the worst case, could have a time complexity of O(m*n), where 'm' is the number of rows in the Queries
table and 'n' is the number of rows in the NPV
table. However, well-indexed databases typically perform this operation much more efficiently, often closer to O(m + n) or even logarithmic time if appropriate indexes are present on the id
and year
columns of both tables.
Note: The specific time complexity can vary significantly depending on factors like database indexing, table sizes, and query optimization techniques employed by the database management system. The provided O(m*n) represents a worst-case theoretical upper bound, while in practice, it is usually far more efficient.